(I) H2O2+O3⟶H2O+2O2 (II) H2O2+Ag2O⟶2Ag+H2O+O2Role of hydrogen peroxide in the above reactions is respectively

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$(I) H_{2} O_{2} + O_{3} ⟶ H_{2} O + 2 O_{2}$

$(II) H_{2} O_{2} + {Ag}_{2} O ⟶ 2 Ag + H_{2} O + O_{2}$

Role of hydrogen peroxide in the above reactions is respectively

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Oxidizing in (I) and (II)

reducing in (I) and (II)

Oxidizing in (I) and reducing in (II)

reducing in (I) and Oxidizing in (II)

answer is C.

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Detailed Solution

$H_{2} O_{2} + O_{3} \to H_{2} O + O_{2}$
In the above reaction, H₂O₂ acts as a reducing agent.
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In the above reaction, H2O2 acts as a reducing agent, it reduces Ag⁺ to Ag.

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