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Q.

I had Rs.14.40 in one- rupee coins and 20 paise coins when I went out shopping. When I returned, I had as many 1 rupee coins as I originally had 20 paise coins and as many 20 paise coins as I originally had 1 rupee coins. Briefly I came back with about one third of what I had started out with. How many 1 rupee coins did I have initially?



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a

10

b

12

c

14

d

16 

answer is C.

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Detailed Solution

Concept: Let's say that there are x 1 rupee coins and 20 paisa coins. We also know that 20 paise is equivalent to 0.2 rupees. He therefore starts off with Rs. 14.40. Consequently, the formula is x+0.2y=14.40.
After shopping, the sum becomes one-third of Rs. 14.40 after the number of rupee and 20 peso coins swap. Therefore, create a fresh equation and resolve it.
We are informed that the amount in question is Rs. 14.40 in one-rupee and 20-praise coins. Consequently, let's assume that there are x rupee coins and y 20-paise coins. Therefore,can be written as 20 paisa = 0.2 rupees. So,  x+0.2y=14.40  (eq.1) 
After shopping, he had one rupee coins because he had 20 paise coins initially and one rupee coins because he had 20 paise coins initially. The amount of 20 paisa coins becomes x, and the number of 1 rupee coins becomes y, once we've finished shopping.
And he had gone shopping with just one-third of the money that had been allocated to him.
After shopping, there was $4.80 left over (1314.40) .
After making a purchase, we can write 0.2x+y=4.80  (eq.2) 
Now, we have
x+0.2y=14.40
x=14.40-0.2y from equation (1) 
Putting the value of ‘x’ in Equation (2)-
0.2x+y=4.80 
0.2(14.40-  0.2 y) + y=4.80
2.88-0.04y+y=4.80
0.96y=1.96
y=2
Adding y=2 to equation (1) results in the following: x=14.40−0.2y
=14.40-0.2(2) 
=14.40-0.40
=14.
So, we thought that x was the amount of one-rupee coins.
Therefore, x in this case equals 14.
Hence, the answer is option 3.
 ExamType: CBSE
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