Q.

I have a total of 300 in coins of denominations 1,  2, and  5. The number of ₹2 coins is 3 times the number of ₹5 coins. The total number of coins is 160. How many coins of each denomination are with me?

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Detailed Solution

The total sum of money = ₹300

Let the number of 5 coins be x, the number of 2 coins be 3x and the number of 1 coin be 160(x+3x)=1604x160-\left(x+3x\right)=160-4x

According to the question, 5×x+2×(3x)+1×(1604x)=3005\times x+2\times\left(3x\right)+1\times\left(160-4x\right)=300

 5x+6x+1604x=300\Rightarrow\ 5x+6x+160-4x=300

 7x+160=300\Rightarrow\ 7x+160=300

7x+160160=300160\Rightarrow7x+160-160=300-160

[Subtracting 160 from both sides]

 7x=140\Rightarrow\ 7x=140

 7x7=1407\Rightarrow\ \frac{7x}{7}=\frac{140}{7}

[Dividing both sides by 7]

x = 20

Hence, the number of coins of 5 denomination = 20

Number of coins of 2 denomination = 3 x 20 = 60

Number of coins of 1 denomination = 160 - 4 x 20 = 160 - 80 = 80

 

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