‘I’ is the perpendicular bisector of side BC of △ABC meeting the circumference of the triangle of M opposite to A then

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

∠MBC=∠MCB

∠BCM=∠BAM

∠CMB=∠CAM

∠BAM=∠CAM

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

An arc in a circle subtends equal angles anywhere on the circumference.
BM is the chord.
∠BCM=∠BAM
Hence, option 2) is correct.
1) ∠MBC=∠MCB
∠MBC is subtended at the arc MC and the angle ∠MCB is subtended at the arc BM.
For the property, the angles should be subtended at the same arc.
Therefore, option 1) is incorrect.
3) ∠CMB=∠CAM
∠CMB is subtended at the arc BC and the angle ∠CAM is subtended at the arc CM.
For the property, the angles should be subtended at the same arc.
Therefore, option 3) is incorrect.
4) ∠BAM=∠CAM
∠BAM is subtended at the arc BM and the angle ∠CAM is subtended at the arc CM.
For the property, the angles should be subtended at the same arc.
Therefore, option 4) is incorrect.
So, Option 2 is correct.

Watch 3-min video & get full concept clarity