I) The word mole was introduced by Avogadro.
II) 1 mole of any substance contain $6.022 \times 10^{23}$ particles.

III) Both 106 g of sodium carbonate and 12 g of carbon have the same number of carbon atoms.

IV) The weight of a molecule of a compound $C_{60} H_{122} is 1.4 \times 10^{- 21} g$

Choose the correct representation (T-True, F-False)

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I – F, II – T, III – F, IV – T

I – T, II – T, III – T, IV – F

I – F, II – T, III – T, IV – T

I – F, II – T, III – T, IV – F

answer is B.

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Detailed Solution

{Na}_{2} {CO}_{3} \to 106 g

is contains 1 mole carbons.

$12 g of carbon \to$ 1 mole carbon

$M {.W of C}_{60} H_{122} = 60 \times 12 + 122 \times 1 = 720 + 122 = 842$

Weight of 1 molecule of $C_{60} H_{122} = \frac{842}{6.023 \times 10^{23}} = 1.39 \times 10^{- 23} g$

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