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I walk from my house to my office at a speed of 3 km/hr and arrive at the office 20 min. late, but when I walked at 4 km/hr. I reached the office 15 minutes before time, the distance between my house and office is

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6 km

7 km

8 km

9 km

answer is B.

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Detailed Solution

Formula : $D = S \times T$

Speed $=$ 3 km/hr

Time $= (T + \frac{1}{3}) h r$

Speed $=$ 4km/hr

Time $= (T - \frac{1}{4}) h r$

$3 (T - \frac{1}{4}) = 4 (T - \frac{1}{4})$

$3 T + 1 = 4 T - 1$

$∴ T = 2 h o u r s$

$∴ D = 3 [2 + \frac{1}{3}]$

$= 3 [\frac{7}{3}]$

$= 7 k m$

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