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Q.

i) Z+LiAlH4X+2LiF+3AlF3 
ii)  X+6H2OY+6H2
iii)  3X+3O2ΔB2O3+3H2O
Then X,Y and Z are respectively

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a

B2H6,B(OH)3,BF3

b

B2H6,B(OH)4,BF3

c

B2O3,B(OH)3,BF3

d

HBO2,B(OH)3,BF3

answer is A.

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Detailed Solution

x=B2H6,y=B(OH)3

z=BF3

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