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I₁, I₂, I₃ of an element are 176, 346 and 1850K. calls respectively. The molecular formula of its phosphate is

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MPO₄

M₂(PO₄)₃

M₃PO₄

M₃(PO₄)₂

answer is D.

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Detailed Solution

From the given Ionization values, we can observe sudden jump from I₂ to I₃.

So, The valence of element(M)=2

$M^{+ 2} {PO}_{4}^{- 3}$

Hence the formula is $M_{3} {({PO}_{4})}_{2}$

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