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Q.

i^×a^×i^+j^×a^×j^+k^×a^×k^ is always equal to 

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a

a

b

-a

c

2a

d

-2a

answer is C.

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Detailed Solution

a-(a·i)i+a-(a·j)j+a-(a·k)k let  a=xi+yj+zk 3a-xi-yj-zk=3a-a=2a

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