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Q.

Ice at –5°C is heated to become vapor with temperature of 110°C at atmospheric pressure. The entropy change associated with this process can be obtained from :

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a

268K383KCpdT+ΔHmelting 273+ΔHboiling 373

b

268K383KCpdT+qrevT

c

268K273KCp,mTdT+ΔHm, fusion Tf+ΔHm, vaporisation Tb+273K373KCp,mdTT+373K383KCp,mdTT

d

268K273KCp,mdT+ΔHm, fusion Tf+ΔHm, vaporistion Tb+273K373KCp,mdT+373K383KCp,mdT

answer is B.

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Detailed Solution

 Ice  Ice  Water  Water  Water  vapour  Water  vapour 

Question Image

ΔSoverall =ΔS1+ΔS2+ΔS3+ΔS4+ΔS5 ΔS2=ΔHm fusion 273 Tf=273 'K ΔS3=273373Cp,mdTTΔS4=ΔHm vaporisation 373 Tb=373KΔS5=373383Cp,mdTT

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