Iceberg floats in sea water with a part of it submerged. The percentage fraction of the ice berg submerged is (Density of ice : 0.9 g ${\mathrm{cm}}^{-3}$, density of sea water : I . I g $\mathrm{cm}{ }^{-3}$)

V be the volume of the iceberg, x be the volume out of sea water.

The iceberg is floating in sea water then

${\mathrm{V\rho }}_{\mathrm{ice}}\mathrm{g} = (\mathrm{V}-\mathrm{x}){\mathrm{\rho }}_{\mathrm{sea} \mathrm{water}}\mathrm{g}$

or $\mathrm{V} \times 0.9\times \mathrm{g} = (\mathrm{V}-\mathrm{x})1.1 \mathrm{g}$

0.2 V = 1.1x

$\therefore \frac{\mathrm{x}}{\mathrm{V}} = \frac{0.2}{1.1}$

Percentage of fraction of the volume of iceberg above the level of sea water

 $\frac{\mathrm{x}}{\mathrm{V}}\times 100 = \frac{0.2}{1.1}\times 100 = 18\%$