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Identical packets are dropped from two airplanes, one above the equator and one above the north pole, and both are dropped from the same height $h$ . Is it true that both packets will take equal time to reach the ground?

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True

False

answer is B.

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Detailed Solution

The above statement is False
Initial velocity of the packets will be zero.
So,

u = 0

a = g

s = h

Applying equation of motion:

s = ut + \frac{1}{2} a t^{2}

Putting all the values

\Rightarrow

h = 0 + \frac{1}{2} g t^{2}

\Rightarrow

t = \sqrt{\frac{2 h}{g}}

Here we can see t

α

\frac{1}{\sqrt{g}}

Poles have a greater value of g as compared to the equator. Hence, a packet dropped at the north pole will reach the ground first.
The correct statement would be that both packets take different times to reach the ground.

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