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Q.

Identify correct conversion during acidic hydrolysis from the following :
(A) starch gives galactose.
(B) cane sugar gives equal amount of glucose and fructose.
(C) milk sugar gives glucose and galactose.
(D) amylopectin gives glucose and fructose.
(E) amylose gives only glucose.
Choose the correct answer from the options given below :

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a

(C), (D) and (E) only

b

(A), (B) and (C) only

c

(B), (C) and (D) only

d

(B), (C) and (E) only

answer is C.

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Detailed Solution

$(A) Starch \overset{H^{+} / H_{2} O}{\to} Glucose (B) \underset{(sucrose)}{Cane sugar} \overset{H^{+} / H_{2} O}{\to} \underset{50 %}{Glucose} + \underset{50 %}{fructose} (C) \underset{(lactose)}{Milk sugar} \overset{H^{+} / H_{2} O}{\to} Glucose + galactose (D) Amylopectin \overset{H^{+} / H_{2} O}{\to} Glucose (E) Amylose \overset{H^{+} / H_{2} O}{\to} Glucose$

So, correct options are B, C and E only

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Identify correct conversion during acidic hydrolysis from the following :(A) starch gives galactose.(B) cane sugar gives equal amount of glucose and fructose.(C) milk sugar gives glucose and galactose.(D) amylopectin gives glucose and fructose.(E) amylose gives only glucose.Choose the correct answer from the options given below :