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Identify M and N in the following reaction.
Copper glance $\overset{C o n t r o l l e d h e a t i n g i n p r e s e n c e o f a i r}{\to} M + S O_{2,} M + N \to S O_{2} + C u$

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$M = C u_{2} O; N = S e l f r e d u c t i o n$

$M = C u_{2} O + C u_{2} S; N = o n l y h e a t i n g$

$M = C u_{2} O; N = C a r b o n R e d u c t i o n$

$M = C u_{2} O; N = E l e c t r o l y t i c r e d u c t i o n$

answer is B.

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Detailed Solution

$C u_{2} S \overset{A i r}{\to} C u_{2} O + C u_{2} S + S O_{2} C u_{2} O + C u_{2} S \overset{}{\to} C u + S O_{2}$

Air blasting is restarted for partial roasting before self reduction, until two-thirds of $C u_{2} S$ is converted into $C u_{2} O$ .

after this, only heating is continued for the self reduction.

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