Identify the correct order of solubility of Na₂S, CuS and ZnS in aqueous solution

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$CuS > ZnS > {Na}_{2} S$

${Na}_{2} S > ZnS > CuS$

$ZnS > {Na}_{2} S > CuS$

${Na}_{2} S > CuS > ZnS$

answer is D.

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Detailed Solution

Na₂S is freely soluble in water. K_sp of group II (CuS) is less than the K_sp of group IV (ZnS) ions. Thus correct order is Na₂S > ZnS > CuS
(More the K_sp, for similar compounds more is the solubility)

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