Identify the correct statement for ${\mathrm{B}}_2{\mathrm{H}}_6$ from those given below.

(A) $\text{ In }{\mathrm{B}}_2{\mathrm{H}}_6\text{, all }\mathrm{B}-\mathrm{H}\text{ bonds are equivalent. }$

(B) $\text{ In }{\mathrm{B}}_2{\mathrm{H}}_6\text{ there are four }3\text{-centre-2-electron bonds. }$

(C) ${\mathrm{B}}_2{\mathrm{H}}_6\text{ is a Lewis acid. }$

(D) ${\mathrm{B}}_2{\mathrm{H}}_6\text{ can be synthesized form both }{\mathrm{BF}}_3\text{ and }{\mathrm{NaBH}}_4$ 

(E) ${\mathrm{B}}_2{\mathrm{H}}_6\text{ is a planar molecule. }$