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In aqueous solution, both NaI and KI dissolve Iodine to form $I_{3}^{-}$

In aqueous solution both KI and RbI dissolve iodine to form $I_{3}^{-}$

NaF has a lower M.P than NaI

A solution of sodium metal in liquid NH3 act as a reducing agent due to the presence of NaH

answer is A, B.

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Detailed Solution

a) In aqueous solution, both NaI and KI dissolve Iodine to form $I_{3}^{-}$
b) In aqueous solution both KI and RbI dissolve iodine to $I_{3}^{-}$

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