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Identify the correct statement with respect to genetic code.

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60 codons of genetic code, code for amino acids and 4 codons do not code for any amino acid.

All the terminating codons start with the nucleotide U

2 nucleotides make one codon

AUG and AAU code for methionine

answer is B.

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Detailed Solution

UAG, UGA, UAA are stop codons
61 codons code for 20 amino acids and 3 codons do not code for any amino acid.
3 nucleotides make one codon.
AUG codes for methionine. It is unique codon. AAU code for amino acid Asparagine.

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