Identify the correct trend given below: (Atomic no. Ti : 22, Cr: 24 and MO : 42)

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$Δ_{0}$ of ${[Cr {(H_{2} O)}_{6}]}^{2 +} < {[Mo {(H_{2} O)}_{6}]}^{2 +}$ , and $Δ_{0}$ of ${[Ti {(H_{2} O)}_{6}]}^{3 +} > {[Ti {(H_{2} O)}_{6}]}^{2 +}$

$Δ_{0}$ of ${[Cr {(H_{2} O)}_{6}]}^{2 +} < {[Mo {(H_{2} O)}_{6}]}^{2 +}$ , and $Δ_{0}$ of ${[Ti {(H_{2} O)}_{6}]}^{3 +} < {[Ti {(H_{2} O)}_{6}]}^{2 +}$

$Δ_{0}$ of ${[Cr {(H_{2} O)}_{6}]}^{2 +} > {[Mo {(H_{2} O)}_{6}]}^{2 +}$ , and $Δ_{0}$ of ${[Ti {(H_{2} O)}_{6}]}^{3 +} < {[Ti {(H_{2} O)}_{6}]}^{2 +}$

$Δ_{0}$ of ${[Cr {(H_{2} O)}_{6}]}^{2 +} > {[Mo {(H_{2} O)}_{6}]}^{2 +}$ , and $Δ_{0}$ of ${[Ti {(H_{2} O)}_{6}]}^{3 +} > {[{Ti}_{2} {(H_{2} O)}_{6}]}^{2 +}$

answer is A.

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Detailed Solution

The higher the oxidation state of the metal, the more stable the complex and higher is $Δ_{0}$ value. The stability of the complex decreases with increasing size of the central metallic ion having the same charge number. This is reflected in the decrease in the value of $Δ_{0}$ .

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