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Identify the elements X and Y using the ionization energy values given below:
Ionization energy (kJ/mol)

$1^{s t}$ $2^{n d}$
X 495 4563
Y 731 1450

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$X = N a; Y = M g$

$X = M g; Y = N a$

$X = M g; Y = F$

$X = F; Y = M g$

answer is A.

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Detailed Solution

For X, $I P_{1} < < < I P_{2}$ Therefore, the second electron is in (n-1) orbit – hence X is Na

For Y, $I P_{1} < I P_{2}$ Therefore, the second electron is in (n) orbit– hence Y is Mg

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