Identify the oxidizing agent and reducing agent respectively in the given equation.
$SnC l_{2} (a q) + 2FeC l_{3} (a q) \to Sn C l_{4} (a q) + 2FeC l_{2} (a q)$

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${SnCl}_{2}, {FeCl}_{3}$

${FeCl}_{3}, {SnCl}_{2}$

${SnCl}_{2}, {SnCl}_{4}$

${FeCl}_{3}, {FeCl}_{2}$

answer is B.

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Detailed Solution

In a given reaction,

FeC l_{3}

acts as oxidizing agent and

SnC l_{2 (a q)}

acts as reducing agent. Since the element Sn has low reduction potential whereas Fe has high reduction potential. Hence, the element Sn loses its electrons reduces the other element iron (Fe).

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