Identify the oxidizing agent and reducing agent respectively in the given equation.

$\text{SnC}{l}_2\left(aq\right)+\text{2FeC}{l}_3\left(aq\right)\to \text{Sn}C{l}_4\left(aq\right)+\text{2FeC}{l}_2\left(aq\right)$

In a given reaction, $\text{FeC}{l}_3$  acts as oxidizing agent and $\text{SnC}{l}_{2\left(aq\right)}$ acts as reducing agent. Since the element Sn has low reduction potential whereas Fe has high reduction potential. Hence, the element Sn loses its electrons reduces the other element iron (Fe).