Identify the product Y in the sequence 

CH₃CHO+CH₃MgI→^EtherX→^H₂O/H+Y

Solution to the given question:

The question involves a sequence of reactions, starting with acetaldehyde (CH3CHO) and methylmagnesium iodide (CH3MgI), followed by an ether intermediate (X), and finally treated with H2O/H+ to give product Y.

Let's break down the reactions step by step:

1. Reaction with CH3CHO and CH3MgI:

   • CH3CHO (acetaldehyde) reacts with CH3MgI (a Grignard reagent).
   • The Grignard reagent (CH3MgI) acts as a nucleophile, attacking the carbonyl group of acetaldehyde. This forms a tetrahedral intermediate that, after hydrolysis, will produce 2-butanol (a secondary alcohol).

   So, the product after this step is 2-butanol (CH3CH(OH)CH3).

2. Ether X:
   • The intermediate, X, is an ether that forms during the reaction between CH3CHO and CH3MgI, before being treated with water.
3. Hydrolysis step (H2O/H+):
   • After hydrolysis with H2O/H+, the ether is converted into an alcohol. Specifically, the intermediate ether will undergo hydrolysis to form 2-butanol (CH3CH(OH)CH3).
4. Final product Y:
   • The final product Y is 2-butanol, which has the structure CH3CH(OH)CH3. This is a secondary alcohol where the hydroxyl group (-OH) is attached to the second carbon in the chain.

Answer:

The correct product Y is 2-butanol, which corresponds to option C.

Thus, the correct option is: c) (CH3)2CHOH

This is the C option, and it is indeed the correct answer.