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Identify the reactions that includes inhibitors in the reactions mixture.

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$N_{2} + 3 H_{2} \frac{Fe}{CO / H_{2} S} 2 {NH}_{3}$

$RCOCl + H_{2} \underset{{BaSO}_{4}}{\overset{Pd}{⟶}} {RCH}_{3}$

$Vegetable Oil + H_{2} \overset{Ni}{⟶} Vegetable ghee.$

$N_{2} + 3 H_{2} \underset{Mo}{\overset{Fe}{⟶}} 2 {NH}_{3}$

answer is C, D.

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Detailed Solution

RCOCl +H₂ $\overset{Pd - {BaSO}_{4}}{\to}$ RCH₃

Barium sulphate reduces the activity of Pd as it has a low surface area.

N₂+3H₂ $\to_{CO / H_{2} S}^{Fe}$ 2NH₃

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