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Q.

Identify Z in the following sequence of reactions ${CH}_{2} = {CH}_{2} \to_{}^{HBr} X \to_{}^{aq. KOH} Y \to_{}^{H_{2} {SO}_{4} / Δ} Z$

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a

${CH}_{2} = {CH}_{2}$

b

${CH}_{3} - {CH}_{2} - OH$

c

${CH}_{3} - {CH}_{2} - Br$

d

${CH}_{3} - {CH}_{2} - CN$

answer is D.

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Detailed Solution

${CH}_{2} = {CH}_{2} \to_{}^{HBr} {CH}_{3} {CH}_{2} Br \to_{}^{aq. KOH} {CH}_{3} {CH}_{2} OH \to_{}^{H_{2} {SO}_{4} / Δ} {CH}_{2} = {CH}_{2}$

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