Q.

If α  is the fifth root of unity then

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a

|1+α+α2+α3+α4|=0

b

|1+α+α2+α3|=1

c

|1+α+α2|=2cosπ5

d

|1+α|=2cosπ10

answer is Û.

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Detailed Solution

we have α=cos2π5+isin2π5 and 1+α+α2+α3+α4=0

               |1+α+α2+α3|=|α4|=|α4|=1

Also, |1+α+α2|=|α3(1+α)|=|1+α|...................(i)

                               =|1+cos2π5+isin2π5|

                               =|2cosπ5(cosπ5+isinπ5)|=2cosπ5

Again from (i), |1+α|=|1+α+α2|=2cosπ5

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