If 3713=2+1x+1y+1z where x,y,z are positive integers , then x,y,z=

3713=2+1x+1y+1z 3713=2+1113=2+11311 =2+11+211 =2+11+1112=2+11+15+12 ⇒x=1,y=5,z=2

If 3713=2+1x+1y+1z where x,y,z are positive integers , then x,y,z=

3713=2+1x+1y+1z 3713=2+1113=2+11311 =2+11+211 =2+11+1112=2+11+15+12 ⇒x=1,y=5,z=2

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If $\frac{37}{13} = 2 + \frac{1}{x + \frac{1}{y + \frac{1}{z}}}$ where $x, y, z$ are positive integers , then $x, y, z =$

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Detailed Solution

\frac{37}{13} = 2 + \frac{1}{x + \frac{1}{y + \frac{1}{z}}}

$\frac{37}{13} = 2 + \frac{11}{13} = 2 + \frac{1}{\frac{13}{11}}$

$= 2 + \frac{1}{1 + \frac{2}{11}}$

$= 2 + \frac{1}{1 + \frac{1}{\frac{11}{2}}} = 2 + \frac{1}{1 + \frac{1}{5 + \frac{1}{2}}}$

$\Rightarrow x = 1, y = 5, z = 2$

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If 3713=2+1x+1y+1z where x,y,z are positive integers , then x,y,z=

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If $\frac{37}{13} = 2 + \frac{1}{x + \frac{1}{y + \frac{1}{z}}}$ where $x, y, z$ are positive integers , then $x, y, z =$