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Q.

If $a + b + c = 6$ and $a^{2} + b^{2} + c^{2} = 34$ , then $a b + b c + c a =$

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a

2

b

1

c

0

d

4

answer is B.

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Detailed Solution

{(a + b + c)}^{2} = a^{2} + b^{2} + c^{2} + 2 (a b + b c + c a)

$6^{2} = 34 + 2 (a b + b c + c a)$

$36 - 34 = 2 (a b + b c + c a)$

$2 = 2 (a b + b c + c a)$

$∴$ $a b + b c + c a = 1$

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If a+b+c=6 and a2+b2+c2=34 , then ab+bc+ca=