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Q.

If α and β are the zeroes of the quadratic polynomial x2+10x+30  then find the quadratic polynomial whose zeroes are α+2β and 2α+ β.


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a

x2+30x+230

b

x2+30x-230

c

x2-30x+230

d

x2-30x-230  

answer is A.

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Detailed Solution

Given, α and β are the zeroes of the quadratic polynomial x2+10x+30.
We know that, the relationship between zeroes and coefficient of quadratic polynomial is
Sum of Zeroes=-Coefficient of xCoefficient of x2  and Product of Zeroes=Constant TermCoefficient of x2.
Then, we get,
α+β=-101=-10 and
αβ=301=30        … (1)
We have to find out quadratic polynomial whose zeroes are α+2β and 2α+ β.
Let α'and β' are the new zeroes then,
α'=α+2β and β'=2α+ β.
Then,
α'+β'=α+2β+2α+ β α'+β'=3α+3β α'+β'=3(α+β) α'+β'=3(-10)                   {using equation (1)}
α'+β'=-30                … (2)
And,
α'β'=(α+2β)(2α+ β) α'β'=2α2+2β2+5αβ α'β'=2(α2+β2)+5×30             {using equation (1)}
α'β'=2(α2+β2)+150           … (3)
Now,
α+β=-10. On squaring both sides,
(α+β)2=-102       {(a+b)2=a2+b2+2ab}
α2+β2+2αβ=100 α2+β2+2×(30)=100       {using equation (1)}
α2+β2+60=100 α2+β2=40 Using above value in equation (3),
α'β'=2×40+150=80+150=230         … (4)
Then,
Quadratic Polynomial=x2-Sum of zeroesx+(Product of zeroes)
Quadratic Polynomial=x2-α'+β'x+α'β'
Quadratic Polynomial=x2--30x+230
Quadratic Polynomial=x2+30x+230
Therefore, the quadratic polynomial whose zeroes are α+2β and 2α+ β is x2+30x+230.
Hence, option (1) is correct.
 
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