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Q.

If  γ  is the ratio of two specific heats of a gas, the number of degrees of freedom of a molecule of the gas is:

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a

252(γ-1)

b

3γ12γ1

c

2γ1

d

92(γ-1)

answer is C.

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Detailed Solution

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molar specific heat of a gas at constant volume is Cv=f.R2  here f is degree of freedom ,   R is universal gas constant  from difference of specific heatsCp=Cv+R  substitute the value of Cv =fR2+R=fR12+1f  Cp=fR(f+22f)specific heat ratio γ=CpCv , substitute the values of specific heats  =fRf+22ffR2 γ=f+2f γ=1+2f 2f=γ-1 degree of freedom is f=2γ1

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