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Q.

If origin is the orthocentre of a triangle formed by the points (cosα,sinα,0) , (cosβ,sinβ,0) , (cosγ,sinγ,0)  then cos(2αβγ)=

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a

0

b

1

c

2

d

3

answer is D.

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Detailed Solution

OA=cos2α+sin2α=1 = OB = OC

            Δ ABC is an equilateral Δe .

            cosα+cosβ+cosγ=sinα+sinβ+sinγ=0                                                      

            Σcos(2αβγ)=3

 

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