If the area of a triangle is $24a^2$ sq. units and height is 8a units then base of the triangle is   

Given area of a triangle=$24a^2$ sq. units

We know that area of a triangle$=\frac{1}{2}\times b\times h$

Given height$\text{=8a}\text{units}$

$\therefore \frac{1}{2}\times b\times h=24a^2$

$\frac{1}{2}\times b\times 8a=24a^2$

$b=\frac{48a^2}{8a}=6a$

$\therefore$ Base of the triangle=6a units