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If the dissociation constants of two weak acids $H A_{1}$ and $H A_{2}$ are $K_{1}$ and $K_{2}$ then the relative strengths of $H A_{1}$ to $H A_{2}$ are given by

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$K_{1} / K_{2}$

$K_{2} / K_{1}$

$\sqrt{K_{1} / K_{2}}$

$\sqrt{K_{2} / K_{1}}$

answer is C.

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Detailed Solution

Strength of $H A_{1}$ /Strength of $H A_{2} = \sqrt{K_{1} / K_{2}} .$

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