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If $x^{3} - 3 x^{2} + 4 x - 4$ is a polynomial, then one of its factors is

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x - 1

x + 1

x - 2

x + 4

answer is C.

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Detailed Solution

x = 2

$\Rightarrow f (2) = 2^{3} - 3 {(2)}^{2} + 4 (2) - 4$

$= 8 - 12 + 8 - 4$

$= 16 - 16$

$= 0$

$∴ (x - 2)$ is a factor of $f (x)$

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