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If $ϕ = 0.4 \cos (100 t)$ weber/turns and number of turns is 5 in the coil, the maximum induced emf is:

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400V

40V

200V

20V

answer is C.

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Detailed Solution

$e = - N \frac{d ϕ}{d t}$

$\begin{array}{l} = - 5 \frac{d}{d t} [0.4 \cos (100 t)] \\ = 5 \times 0.4 \times 100 \sin (100 t) \\ = 200 \sin (100 t) \end{array}$

Compare by the relation $ε = ε_{0} \sin ω t$

$ε_{0} = 200 V and ω = 100$

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