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Q.

If $ε_{0}$ and $μ_{0}$ , represent the permittivity and permeability of free space respectively then the dimension of the product $ε_{0}$ $μ_{0}$ is:

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a

$M^{0} L^{- 1} T$

b

$M^{0} L^{2} T^{- 2}$

c

$M^{0} L T^{- 1}$

d

$M^{0} L^{- 2} T^{2}$

answer is A.

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Detailed Solution

$v = \frac{1}{\sqrt{μ_{0} ε_{0}}} \to μ_{0} ε_{0}$ $= \frac{1}{v^{2}}$

$\frac{1}{{(L T^{- 1})}^{2}} = L^{- 2} T^{+ 2}$

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