If ∫0∞e−x2dx=π2 then match the following Column-I Integrals Column-II valuesA)∫0∞e−3x2dx=p)π6B)∫−∞∞e−3x2dx=q)12π3C)∫−∞∞1x2e−1/x2dx=r)3π3D)∫0∞e−tx2dx at t =9 iss)π2

A:Sub 3x=t B: 2∫0∞e−3x2dxC:Sub 1x=tD:Sub 3x=t

If ∫0∞e−x2dx=π2 then match the following Column-I Integrals Column-II valuesA)∫0∞e−3x2dx=p)π6B)∫−∞∞e−3x2dx=q)12π3C)∫−∞∞1x2e−1/x2dx=r)3π3D)∫0∞e−tx2dx at t =9 iss)π2

A:Sub 3x=t B: 2∫0∞e−3x2dxC:Sub 1x=tD:Sub 3x=t

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$I f \int_{0}^{\infty} e^{- x^{2}} d x = \frac{\sqrt{π}}{2}$ then match the following
Column-I
Integrals Column-II
values
A) $\int_{0}^{\infty} e^{- 3 x^{2}} d x =$ p) $\frac{\sqrt{π}}{6}$
B) $\int_{- \infty}^{\infty} e^{- 3 x^{2}} d x =$ q) $\frac{1}{2} \sqrt{\frac{π}{3}}$
C) $\int_{- \infty}^{\infty} \frac{1}{x^{2}} e^{- 1 / x^{2}} d x =$ r) $\frac{\sqrt{3 π}}{3}$
D) $\int_{0}^{\infty} e^{- t x^{2}} d x a t t = 9 i s$ s) $\frac{\sqrt{π}}{2}$

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$A \to p; B \to r; C - s; D \to q$

$A \to q; B \to s; C - r; D \to p$

$A \to q; B \to r; C - s; D \to p$

$A \to s; B \to r; C - q; D \to p$

answer is B.

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$A:Sub \sqrt{3} x = t \begin{array}{l} B: 2 \int_{0}^{\infty} e^{- 3 x^{2}} d x \\ C : Sub \frac{1}{x} = t \\ D:Sub 3x=t \end{array}$

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	Column-I Integrals		Column-II values
A)	$\int_{0}^{\infty} e^{- 3 x^{2}} d x =$	p)	$\frac{\sqrt{π}}{6}$
B)	$\int_{- \infty}^{\infty} e^{- 3 x^{2}} d x =$	q)	$\frac{1}{2} \sqrt{\frac{π}{3}}$
C)	$\int_{- \infty}^{\infty} \frac{1}{x^{2}} e^{- 1 / x^{2}} d x =$	r)	$\frac{\sqrt{3 π}}{3}$
D)	$\int_{0}^{\infty} e^{- t x^{2}} d x a t t = 9 i s$	s)	$\frac{\sqrt{π}}{2}$

If ∫0∞e−x2dx=π2 then match the following Column-I Integrals Column-II valuesA)∫0∞e−3x2dx=p)π6B)∫−∞∞e−3x2dx=q)12π3C)∫−∞∞1x2e−1/x2dx=r)3π3D)∫0∞e−tx2dx at t =9 iss)π2

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