Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

If (ω1)  is a cube root of unity, then |11+ω1+ω21+ω211+ω1+ω1+ω21|

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

2

b

0

c

–4

d

1

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

|11+ω1+ω21+ω211+ω1+ω1+ω21| 

Apply c1c1+c2+c3 ,

then determinant is

=|21+ω1+ω2211+ω21+ω21|R2R2-R1 , R3R3-R1=2|21+ω1+ω20ωωω20ω+ω2ω2|                 since 1+ω+ω2=0

=2(ω3+ω2ω3ω3+ω4)

=2(ω21+ω)=4

 

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring