If 10 different sweets are to be distributed among 6 children, the probability that a particular child gets 4 sweets is

10 different sweets are to be distributed among 6 children,

$n\left(S\right)=6^{10}$

E= Event in which a particular child gets 4 sweets

$4 \mathrm{biscuits} \mathrm{can} \mathrm{be} \mathrm{selected} \mathrm{from} 10 \mathrm{biscuits} \mathrm{in}{ }^{10}{\mathrm{C}}_4 \mathrm{ways}$

$\mathrm{and} \mathrm{can} \mathrm{be} \mathrm{given} \mathrm{to} \mathrm{particular} \mathrm{boy}$

$$\begin{gathered} \mathrm{the} \mathrm{remaining} 6 \mathrm{biscuits} \mathrm{to} \mathrm{be} \mathrm{distributed} \mathrm{to} \mathrm{other} 5 \mathrm{boys} \\ \therefore n\left(E\right)={ }^{10}{C}_4{\left(5\right)}^6 \end{gathered}$$

$P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}=$$\frac{{ }^{10}{C}_4\times 5^6}{6^{10}}$