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If 100 N force is applied to a 10 kg block as shown in the diagram, the acceleration of the 40 kg slab is

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16.5 m/s²

0.98 m/s²

0.25 m/s²

0.5 m/s²

answer is B.

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Detailed Solution

$\begin{array}{l} f_{s} = μ_{s} mg = 58.8 N > F \\ f_{k} = μ_{k} mg = 39.2 N \\ a = \frac{f_{k}}{M} = \frac{39.2}{40} = 0.98 m / s^{2} \end{array}$

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