Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8

Q.

If 1021 molecules are removed from 200 mg of CO2, then the number of moles of CO2 left are

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

1.68×102

b

2.87×103

c

28.8×103

d

0.288×103

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Molar mass of CO2​ = 44 g

Given mass = 200 mg = 0.2 g

Number of moles = 0.244​= 1220

Number of moles = number of moleculesAvogadro's number

⇒ Number of molecules = Avogadro’s number x number of moles

⇒ No. of molecules = 6.022 × 1023 × 1220​ = 2.73 × 1021 molecules in 1220 ​moles

As 1021 molecules  are removed,

∴ No. of molecules left = 2.73×1021 − 1021 = 1.73 × 1021

∴ No. of moles = No. of moleculesAvogadro's number​ = 1.73 × 10216.023 × 1023

                             = 2.87 × 10−3

Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon