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If $ω_{1}, ω_{2}, ω_{3}, ω_{4}$ are angular velocities of rotation of earth, seconds hand, minutes hand, hours hand of a watch respectively, these values in decreasing order is

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ω_{2}, ω_{3}, ω_{4}, ω_{1}

ω_{1}, ω_{2}, ω_{3}, ω_{4}

ω_{1}, ω_{4}, ω_{3}, ω_{2}

ω_{4}, ω_{3}, ω_{2}, ω_{1}

answer is B.

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Detailed Solution

ω = \frac{2 π}{T}

$For earth ω_{1} = \frac{2 π}{24 \times 60 \times 60}$

$For seconds hand, ω_{2} = \frac{2 π}{60}$

$For minutes hand, ω_{3} = \frac{2 π}{60 \times 60}$

$For hours hand, ω_{4} = \frac{2 π}{12 \times 60 \times 60}$

$Decreasing order is ω_{2}, ω_{3}, ω_{4}, ω_{1}$

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