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Q.

If 17th term of an A.P. exceeds its 10th term by 7. The common difference is:

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a

1

b

2

c

3

d

4

answer is A.

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Detailed Solution

Explanation: Nth term in AP is:
an = a+(n-1)d
a17 = a+(17−1)d
a17 = a +16d
In the same way,
a10 = a+9d
Given,
a17 − a10 = 7
Therefore,
(a +16d)−(a+9d) = 7
7d = 7

d = 1

Therefore, the common difference is 1.

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