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Q.

If 18 pumps can raise 2170 tonnes water in 10 days, working 7 hours a day then in how many days will 16 pump raise 1736 tonnes of water, working 9 hours a day?


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a

6

b

7

c

8

d

9

answer is B.

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Detailed Solution

Therefore, it is assumed that the efficiency of 16 pumps raising 1736 tonnes of water while operating 9 hours per day over t days is comparable to that of 18 pumps lifting 2170 tonnes of water over the course of 10 days.
Thus, we must determine the t days.
If 18 pumps, operating for 7 hours per day, can elevate 2170 tonnes of water in 10 days. Thus, with an hour of work every day, 18 pumps can elevate 2170 tonnes of water in 70 days.
As a result, 1 pump can elevate 2170 tonnes of water in 70 days and 18 hours of work.
The formula for efficiency is given by η= d×h×n w  .
d 1 × h 1 × n 1 w 1 = d 2 × h 2 × n 2 w 2 18×10×7 2170 = t×9×16 1736 t=7  
Hence, the correct option is 2.
 
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