If $1-e^{\frac{1}{x}-1}>0$  then x is not satisfied by ____ number of integral values

$\frac{e^{\frac{1}{x}}}{e}<1\Rightarrow e^{\frac{1}{x}}<e^1\Rightarrow e^{\frac{1}{x}-1}<1$

                                           $\Rightarrow \frac{1-x}{x}<0$

            $x\in \left(-\infty ,0\right)\cup \left(1,\infty \right)$

            x not satisties the integers 0, 1

                number of values = 2