Q.

If  2 and i are two roots of the equation 2z4+az3+bz2+cz+3=0  where

a,b,c,R  then the  value of 2a11  is _______

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answer is 1.

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Detailed Solution

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α,2,i,i are the roots 
Product of roots  =32

α=34

Nowa2=α+2+iia=112

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