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Q.

If ‘2’ is one of the roots of x2kx+10=0, then the other root is 

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a

7

b

10

c

5

d

-7

answer is A.

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Detailed Solution

x2kx+10=0

If 2 is the one of the root

22k.2+10=0

42k+10=0

2k=14

k=7

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If ‘2’ is one of the roots of x2−kx+10=0, then the other root is