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Q.

If 2 moles of diatomic gas and 1 mole of monatomic gas are mixed, then the ratio of specific heats for the mixture is

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a

73

b

1913

c

1519

d

54

answer is C.

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Detailed Solution

μ1=1,γ1=5/3 (for monatomic gas) and μ2=2,γ2=7/5 (for diatomic gas).

From formula

γmixture =μ1γ1γ11+μ2γ2γ21μ1γ11+μ2γ21=1×53531+2×757511531+2751=52+732+5=1913

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