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Q.

If $2 \tan^{- 1} (\cos x) = \tan^{- 1} (2 \cos e c x)$ then x =

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a

No solution

b

$\frac{π}{4}$

c

$\frac{π}{6}$

d

$\frac{π}{2}$

answer is C.

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Detailed Solution

$\tan^{- 1} (\frac{2 \cos x}{1 - \cos^{2} x}) = \tan^{- 1} (\frac{2}{\sin x})$

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