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Q.

If 20 g of CaCO3 is treated with 20 g of HCl, then how many grams of CO2can be generated with this following equation? CaCO3(s)+2HCl(aq)CaCl2(aq)+H2O(l)+CO2(g)

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a

8.8g

b

12g

c

16g

d

2.2g

answer is B.

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Detailed Solution

CaCO3+2HClCaCl2+H2O+CO2

100g          73g             44g 

20g              20g

20100×44=0.2×44=8.8g

The amount of CO2=8.8 gm

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