Q.

If 20 g of CaCO3 is treated with 20 g of HCl, then how many grams of CO2can be generated with this following equation? CaCO3(s)+2HCl(aq)CaCl2(aq)+H2O(l)+CO2(g)

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*
An Intiative by Sri Chaitanya

a

8.8g

b

12g

c

16g

d

2.2g

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

CaCO3+2HClCaCl2+H2O+CO2

100g          73g             44g 

20g              20g

20100×44=0.2×44=8.8g

The amount of CO2=8.8 gm

Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon