Q.

If 200 mL of 0.1M KHC2O4, 300 mL of O.2M H2C2O4 and 500 mL of 0.3 M NaCl is neutralized by 140 mI of Ca(OH)2. What is its molarity?

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a

2

b

1

c

1.5

d

0.5

answer is B.

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Detailed Solution

Eq. of Ca(OH)2
= Eq. of KHC2O4 + Eq. of H2C2O4
140 x M x 2 = 200 x 0.1x 1+300 x 0.2 x 2
 M =0.5

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